19x^2+37x-150=0

Solution for 19x^2+37x-150=0 equation:

19x^2+37x-150=0

a = 19; b = 37; c = -150;
Δ = b2-4ac
Δ = 372-4·19·(-150)
Δ = 12769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12769}=113$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-113}{2*19}=\frac{-150}{38}
=-3+18/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+113}{2*19}=\frac{76}{38}
=2
$